Vote for Us! (July)

[Jaixe Furiael]

Voted 25

[Ash]

vote #8

[Skeletor]

vote 11 (447/369/2448/1047)

[PepsiYuuka]

Vote 15.

[Amaterasu]

Vote 21 (449/371/2450/1049)

[Cell]

26

[Guu]

Voted: 24

Points go to Guu.

[Summer]

Vote 25!

[Soldier 75]

Vote 3

[PepsiYuuka]

Vote 16. (12 hour)

[Freeza]

27

[Makoto Yuki]

Voted: 20

[Ebonywood Hellscythe]

Voted 23

Have a fun irrelevant maths fact (23 is boring and I've exhausted my supply relating to it).

If you keep flipping an unbiased coin until you get heads, what is the mean number of times you will have to flip it?

[spoiler]2. On average it will take 2 flips. Test it if you want.

Why?

Mean value will be equal to the sum of x*p where x is the flip number and p is the probability of it getting to that many flips. The sum of x*p is equal to S(n) as n -> infinty where S(n) = the sum of r*2^(-r) from r = 1 to r = n. (x = r, p = r*2^(-r))

Hence,

S(n) = 0.5 + 2*0.25 + 3*0.125 + 4*0.0625 + ... + (n-1)/[2^(n-1)] + n/(2^n)
0.5*S(n) = 0.25 + 2*0.125 + 3*0.0625 + 4*0.03125 + ... + (n-1)/(2^n) + n/[2^(n+1)]
S(n) - 0.5*S = 0.5*S = 0.5 + 0.25 + 0.125 + 0.0625 + ... + 1/(2^n) - n/[2^(n+1)]
S(n) = 1 + 0.5 + 0.25 + 0.125 + 0.0625 + ... - n/[2^(n+1)]
S(n) = 2 - n/[2^(n+1)]
As n -> inf, S(n) -> 2[/spoiler]

[Tamsin Suzaku]

Voted: 26 (458/377/2457/1056)

[Soldier 75]

Vote 4

[PepsiYuuka]

Vote 17.

[Cell]

27

[Summer]

Vote 26!

[Makoto Yuki]

Voted: 21

[Amaterasu]

Vote 22 (464/382/2462/1061)