07-08-2017, 09:20 AM
Voted
The definite integral of √(x^2 - 4x - 4) with respect to x between x=6 and x=10 can be expressed in the form:
a√(14) + b√(2) + c*ln(2 + √(2)) + d*ln(e + √(14)
The vote number is equal to a + b + c + d + e.
[spoiler]8
The value of the integral is 8√(14) - 4√(2) + 4ln(2 + √(2)) - 4ln(4 + √(14) ≈ 21.002.
Hence, a = 8, b = -4, c = 4, d = -4, e = 4
so, a + b + c + d + e = 8[/spoiler]
The definite integral of √(x^2 - 4x - 4) with respect to x between x=6 and x=10 can be expressed in the form:
a√(14) + b√(2) + c*ln(2 + √(2)) + d*ln(e + √(14)
The vote number is equal to a + b + c + d + e.
[spoiler]8
The value of the integral is 8√(14) - 4√(2) + 4ln(2 + √(2)) - 4ln(4 + √(14) ≈ 21.002.
Hence, a = 8, b = -4, c = 4, d = -4, e = 4
so, a + b + c + d + e = 8[/spoiler]