06-10-2017, 11:13 AM
Voted
The number of 0s at the end of 48! (1*2*3*4*5*...*48)
[spoiler]10
The number of 0s at the end of a number corresponds to the number of factors of 10. As 10 = 2*5, for a factorial this will equal the number of 5s (as there will always be more 2s than 5s). From 1 to 48, there are 10 factors of 5. 1 from 5, 10, 15, 20, 30, 35, 40, and 45. And 2 from 25.
Which is 10 in total.[/spoiler]
The number of 0s at the end of 48! (1*2*3*4*5*...*48)
[spoiler]10
The number of 0s at the end of a number corresponds to the number of factors of 10. As 10 = 2*5, for a factorial this will equal the number of 5s (as there will always be more 2s than 5s). From 1 to 48, there are 10 factors of 5. 1 from 5, 10, 15, 20, 30, 35, 40, and 45. And 2 from 25.
Which is 10 in total.[/spoiler]