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Omni Archive
Vote for Us! (June) - Printable Version

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+---- Thread: Vote for Us! (June) (/showthread.php?tid=6189)

Pages: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22

RE: Vote for Us! (June) - Alex Mercer - 06-08-2017

Voted: 7

RE: Vote for Us! (June) - Skeletor - 06-08-2017

vote 5 (127/113/1781/382)

RE: Vote for Us! (June) - Amaterasu - 06-09-2017

Vote 8 (128/114/1784/383)

RE: Vote for Us! (June) - Mark - 06-09-2017

Vote 5
129/115/1785/384

RE: Vote for Us! (June) - Zack Fair - 06-09-2017

Voted: 3 (130/116/1785/385)

RE: Vote for Us! (June) - Jim Raynor - 06-09-2017

8

RE: Vote for Us! (June) - Dane Regan - 06-09-2017

Vote number 4^(3/2)

8

RE: Vote for Us! (June) - Summer - 06-09-2017

Vote 9!

RE: Vote for Us! (June) - Eda - 06-09-2017

v8

RE: Vote for Us! (June) - Meriwa - 06-09-2017

Voted 9!

RE: Vote for Us! (June) - Gildarts - 06-09-2017

9

RE: Vote for Us! (June) - Mark - 06-09-2017

Vote 6 (12 hour)
137/122/1793/391

RE: Vote for Us! (June) - Zack Fair - 06-09-2017

Voted: 4 (138/123/1793/392)

RE: Vote for Us! (June) - Guu - 06-09-2017

Voted: 8

RE: Vote for Us! (June) - Odin - 06-09-2017

9

RE: Vote for Us! (June) - Todd Ingram - 06-09-2017

9

RE: Vote for Us! (June) - Amaterasu - 06-09-2017

Vote 9 (12hr) (141/127/1796/395)

RE: Vote for Us! (June) - Tamsin Suzaku - 06-09-2017



Voted: 7 (142/128/1796/396)

RE: Vote for Us! (June) - Dane Regan - 06-09-2017

Voted

The last digit of 3^2198634

Answer:[spoiler]
9

The last digit of the following are:
3^1: 3
3^2: 9
3^3: 7
3^4: 1
3^5: 3
etc. The pattern repeats as the last digit of two numbers being multiplied are the only digits that affect the last digit of the product. Therefore, the last digit of 3^(4n+2) where n is an integer (i.e. a multiple of 4 plus 2) is 9. To tell that 2198634 is a multiple of 4 + 2, look at the last 2 digits: 34. 34 = 32 + 2 = 4*8 + 2. This method works as 4 is a factor of 100.[/spoiler]

RE: Vote for Us! (June) - Arle Nadja - 06-09-2017

Vote 6